How do you write a Program in Java that checks for Leap Years? The Java Leap Year Checker isn’t hard to code, although it does have a lot of conditional logic in there that might trip you up.
One of the classic interview questions every Java developer eventually runs into is, ‘How do you check if a year is a leap year?’
Leap years, of course, are those special years where February gets an extra day, making it 29 instead of 28.
The rules for determining leap years are simple: A year is a leap year if it’s divisible by 4, except for years that are divisible by 100… unless they’re also divisible by 400.
Sounds like a mouthful, right? But in code, it’s straightforward with just a couple of conditionals.
First, we check if the year is divisible by 4. If not, it’s not a leap year—easy.
Next, we see if the year is divisible by 100. If it is, we have one last check to make sure it’s divisible by 400.
If both of these are true, you’ve got yourself a leap year!
And of course, I know what you’re really waiting for—here’s some code to show how it’s done.
So there you have it—a leap year checker in Java. Run it yourself and give it a go!
Once you’ve tried it out, be sure to like and subscribe, and head over to TheServerSide for more awesome Java content!
One of the classic interview questions every Java developer eventually faces is, ‘How do you check if a year is a leap year?’
Leap years, of course, are the ones where February has 29 days instead of the usual 28. But how do you know when a year is a leap year?
The rules are straightforward:
A year is a leap year if it’s divisible by 4.
But wait! If it’s also divisible by 100, it’s not a leap year… unless:
The year is divisible by 400. In that case, it is a leap year!
Breaking this down into steps in code makes the process really simple to follow.
First, check if the year is divisible by 4. If not, it’s not a leap year.
If it is divisible by 4, check if it’s also divisible by 100.
Finally, if it’s divisible by 100, check whether it’s divisible by 400 to make the final decision.
Now let’s see how that looks in code.
Now the conditional logic is broken down into three simple steps, making it much easier to read and understand.
Go ahead and give it a try! And when you’re done, don’t forget to like, subscribe, and check out TheServerSide for more Java interview prep!
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